Question #74147

Angle between the lines x+3=0 and y+7=0

Expert's answer

Answer on Question #74147 – Math – Analytic Geometry

Question

Angle between the lines x+3=0x + 3 = 0 and y+7=0y + 7 = 0

Solution

The angle θ\theta between the lines having slope m1m_1 and m2m_2 is given by


tanθ=±m2m11+m1m2\tan \theta = \pm \frac{m_2 - m_1}{1 + m_1 m_2}


In our problem we have


x+3=0x=3, Vertical linex + 3 = 0 \Rightarrow x = -3, \text{ Vertical line}y+7=0y=t, Horizontal liney + 7 = 0 \Rightarrow y = -t, \text{ Horizontal line}


Then lines are perpendicular.

Therefore, the angle between the lines x+3=0x + 3 = 0 and y+7=0y + 7 = 0 is 9090{}^\circ.

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