Question #62252

A = sin ti + cos tj + tk, evaluate
d2A/dt2

Expert's answer

Answer on Question #62252 – Math – Analytic Geometry

Question


A=sinti+costj+tk,A = \operatorname{sin t} i + \operatorname{cost} j + t k,d2Adt2=?\frac{d^{2} A}{dt^{2}} = ?


Solution

Let's derive vector AA twice:


dAdt=(sint)i+(cost)j+(t)k=costisintj+k,\frac{d A}{d t} = (\sin t)' i + (\cos t)' j + (t)' k = \cos t i - \sin t j + k,d2Adt2=(cost)i(sint)j+(1)k=sinticostj+0k=sintcostj.\frac{d^{2} A}{d t^{2}} = (\cos t)' i - (\sin t)' j + (1)' k = - \sin t i - \cos t j + 0 k = \sin t - \cos t j.


Answer: d2Adt2=sintcostj\frac{d^{2} A}{dt^{2}} = \sin t - \cos t j.

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