Answer on Question #62252 – Math – Analytic Geometry
Question
A=sinti+costj+tk,dt2d2A=?
Solution
Let's derive vector A twice:
dtdA=(sint)′i+(cost)′j+(t)′k=costi−sintj+k,dt2d2A=(cost)′i−(sint)′j+(1)′k=−sinti−costj+0k=sint−costj.
Answer: dt2d2A=sint−costj.
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