Question #60406

Find the gradient of the straight line that passes through the points (5, −3) and (−2, 4).
1

Expert's answer

2016-06-20T08:08:02-0400

Answer on Question #60406 – Math – Analytic Geometry

Question

Find the gradient of the straight line that passes through the points (5,3)(5, -3) and (2,4)(-2, 4).

Solution

The gradient of the linear function in one variable is equal to k=tanφk = \tan \varphi, where φ\varphi is the angle between the given line and the positive direction of the xx-axis.

In this problem


k=y2y1x2x1=4+325=1.k = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 + 3}{-2 - 5} = -1.


Answer: 1-1.

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