Answer to Question #57356 in Analytic Geometry for James

Question

: What are the coordinates of the vertices of the conic section shown below?

(y+2)^2 (x-3)^2
---------- - ---------- = 1
16 9

A: (0, -2) and (6, - 2)
B: (-2, -1) and (-2, 7)
C: (-1, -2) and (7, - 2)
D: (3, -6) and (3, 2)


: What are the coordinates of the foci of the conic section shown below?

(y+2)^2 (x-3)^2
---------- - ----------- = 1
25 4



a: (3 ± √21, -2)

b: (3 ± √29, -2)

c: (3, -2 ± √29)

d: (3, -2 ± √21)


: Which direction does the graph of the equation shown below open?

X^2 + 6x – 4y + 5 = 0

A: up
B: down
C: right
D: left