Answer on Question #57351 – Math – Analytic Geometry
Question
Graph the equations shown below, the graph is scaled 9 high and 9 wide.
X ∧ 2 y ∧ 2 … ⋯ + … ⋯ = 1 20 20 \begin{array}{l l} X ^ {\wedge} 2 & y ^ {\wedge} 2 \\ \dots \dots + & \dots \dots = 1 \\ 2 0 & 2 0 \end{array} X ∧ 2 …⋯ + 20 y ∧ 2 …⋯ = 1 20 6 x ∧ 2 + 6 y ∧ 2 = 144 6 x ^ {\wedge} 2 + 6 y ^ {\wedge} 2 = 1 4 4 6 x ∧ 2 + 6 y ∧ 2 = 144 x ∧ 2 + y ∧ 2 = 16 x ^ {\wedge} 2 + y ^ {\wedge} 2 = 1 6 x ∧ 2 + y ∧ 2 = 16 20 x ∧ 2 − 20 y ∧ 2 = 400 2 0 x ^ {\wedge} 2 - 2 0 y ^ {\wedge} 2 = 4 0 0 20 x ∧ 2 − 20 y ∧ 2 = 400 Solution
1. x 2 20 + y 2 20 = 1 \frac{x^2}{20} + \frac{y^2}{20} = 1 20 x 2 + 20 y 2 = 1 is a circle centered on ( 0 , 0 ) (0,0) ( 0 , 0 ) and with radius of 20 = 2 5 \sqrt{20} = 2\sqrt{5} 20 = 2 5 .
2. 6 x 2 + 6 y 2 = 144 6x^{2} + 6y^{2} = 144 6 x 2 + 6 y 2 = 144 is a circle centered on ( 0 , 0 ) (0,0) ( 0 , 0 ) and with radius of 144 6 = 12 6 = 2 6 \sqrt{\frac{144}{6}} = \frac{12}{\sqrt{6}} = 2\sqrt{6} 6 144 = 6 12 = 2 6 .
3. x 2 + y 2 = 16 x^{2} + y^{2} = 16 x 2 + y 2 = 16 is a circle centered on ( 0 , 0 ) (0,0) ( 0 , 0 ) and with radius of 4.
4. 20 x 2 − 20 y 2 = 400 20x^{2} - 20y^{2} = 400 20 x 2 − 20 y 2 = 400 is a hyperbola centered on ( 0 , 0 ) (0,0) ( 0 , 0 ) with the horizontal transverse axis, a = b = 20 = 2 5 a = b = \sqrt{20} = 2\sqrt{5} a = b = 20 = 2 5 .
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