Question #57350

: Graph the equations shown below, the graph is scaled to 10 high and 10 wide.

X^2 y^2
----- + ------ = 1
64 36


x^2 y^2
----- - ------- = 1
64 36

x^2 y^2
---- - ------ = 1
100 64


x^2 y^2
----- + ------ = 1
100 64

Expert's answer

Answer on Question #57350 – Math – Analytic Geometry

Question

Graph the equations shown below, the graph is scaled to 10 high and 10 wide.


x264+y236=1\frac {x ^ {2}}{6 4} + \frac {y ^ {2}}{3 6} = 1x264y236=1\frac {x ^ {2}}{6 4} - \frac {y ^ {2}}{3 6} = 1x2100y264=1\frac {x ^ {2}}{1 0 0} - \frac {y ^ {2}}{6 4} = 1x2100+y264=1\frac {x ^ {2}}{1 0 0} + \frac {y ^ {2}}{6 4} = 1

Solution

1. x264+y236=1\frac{x^2}{64} + \frac{y^2}{36} = 1

is the equation of ellipse with the semi-major axis a=64=8a = \sqrt{64} = 8, and the semi-minor axis b=36=6b = \sqrt{36} = 6. Then we graph it:



2. x264y236=1\frac{x^2}{64} - \frac{y^2}{36} = 1

is the equation of hyperbola with the semi-major axis a=64=8a = \sqrt{64} = 8 , and the conjugate axis 2b=236=122b = 2\sqrt{36} = 12 . Then we graph it:



3.


x2100y264=1\frac {x ^ {2}}{1 0 0} - \frac {y ^ {2}}{6 4} = 1


is the equation of hyperbola with the semi-major axis a=100=10a = \sqrt{100} = 10 , and the conjugate axis 2b=264=162b = 2\sqrt{64} = 16 . Then we graph it:



4.


x2100+y264=1\frac {x ^ {2}}{1 0 0} + \frac {y ^ {2}}{6 4} = 1


is the equation of ellipse with the semi-major axis a=100=10a = \sqrt{100} = 10 , and the semi-minor axis b=64=8b = \sqrt{64} = 8 . Then we graph it:



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