Answer on Question #57350 – Math – Analytic Geometry
Question
Graph the equations shown below, the graph is scaled to 10 high and 10 wide.
x 2 64 + y 2 36 = 1 \frac {x ^ {2}}{6 4} + \frac {y ^ {2}}{3 6} = 1 64 x 2 + 36 y 2 = 1 x 2 64 − y 2 36 = 1 \frac {x ^ {2}}{6 4} - \frac {y ^ {2}}{3 6} = 1 64 x 2 − 36 y 2 = 1 x 2 100 − y 2 64 = 1 \frac {x ^ {2}}{1 0 0} - \frac {y ^ {2}}{6 4} = 1 100 x 2 − 64 y 2 = 1 x 2 100 + y 2 64 = 1 \frac {x ^ {2}}{1 0 0} + \frac {y ^ {2}}{6 4} = 1 100 x 2 + 64 y 2 = 1 Solution
1. x 2 64 + y 2 36 = 1 \frac{x^2}{64} + \frac{y^2}{36} = 1 64 x 2 + 36 y 2 = 1
is the equation of ellipse with the semi-major axis a = 64 = 8 a = \sqrt{64} = 8 a = 64 = 8 , and the semi-minor axis b = 36 = 6 b = \sqrt{36} = 6 b = 36 = 6 . Then we graph it:
2. x 2 64 − y 2 36 = 1 \frac{x^2}{64} - \frac{y^2}{36} = 1 64 x 2 − 36 y 2 = 1
is the equation of hyperbola with the semi-major axis a = 64 = 8 a = \sqrt{64} = 8 a = 64 = 8 , and the conjugate axis 2 b = 2 36 = 12 2b = 2\sqrt{36} = 12 2 b = 2 36 = 12 . Then we graph it:
3.
x 2 100 − y 2 64 = 1 \frac {x ^ {2}}{1 0 0} - \frac {y ^ {2}}{6 4} = 1 100 x 2 − 64 y 2 = 1
is the equation of hyperbola with the semi-major axis a = 100 = 10 a = \sqrt{100} = 10 a = 100 = 10 , and the conjugate axis 2 b = 2 64 = 16 2b = 2\sqrt{64} = 16 2 b = 2 64 = 16 . Then we graph it:
4.
x 2 100 + y 2 64 = 1 \frac {x ^ {2}}{1 0 0} + \frac {y ^ {2}}{6 4} = 1 100 x 2 + 64 y 2 = 1
is the equation of ellipse with the semi-major axis a = 100 = 10 a = \sqrt{100} = 10 a = 100 = 10 , and the semi-minor axis b = 64 = 8 b = \sqrt{64} = 8 b = 64 = 8 . Then we graph it:
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