Answer on Question #57344 – Math – Analytic Geometry
Question
1. Which conic section does this equation represent?
X ∧ 2 − 4 x + y ∧ 2 + 6 y − 9 = 5 X ^ {\wedge} 2 - 4 x + y ^ {\wedge} 2 + 6 y - 9 = 5 X ∧ 2 − 4 x + y ∧ 2 + 6 y − 9 = 5
A: Parabola
B: Hyperbola
C: Circle
D: Ellipse
Solution
x ∧ 2 − 4 x + y ∧ 2 + 6 y − 9 = 5 x ^ {\wedge} 2 - 4 x + y ^ {\wedge} 2 + 6 y - 9 = 5 x ∧ 2 − 4 x + y ∧ 2 + 6 y − 9 = 5 ( x − 2 ) ∧ 2 − 4 + ( y + 3 ) ∧ 2 − 9 − 9 = 5 (x - 2) ^ {\wedge} 2 - 4 + (y + 3) ^ {\wedge} 2 - 9 - 9 = 5 ( x − 2 ) ∧ 2 − 4 + ( y + 3 ) ∧ 2 − 9 − 9 = 5 ( x − 2 ) ∧ 2 + ( y + 3 ) ∧ 2 = 27 (x - 2) ^ {\wedge} 2 + (y + 3) ^ {\wedge} 2 = 2 7 ( x − 2 ) ∧ 2 + ( y + 3 ) ∧ 2 = 27
It is an equation of circle. Coordinates of centre are ( 2 , − 3 ) (2, -3) ( 2 , − 3 ) and radius is r = 27 = 3 3 r = \sqrt{27} = 3\sqrt{3} r = 27 = 3 3 .
Answer: C: Circle
Question
2. Which conic section is represented by the equation shown below?
9 x + 4 y ∧ 2 + 18 x = 16 9 x + 4 y ^ {\wedge} 2 + 18 x = 16 9 x + 4 y ∧ 2 + 18 x = 16
A: Circle
B: Hyperbola
C: Parabola
D: Ellipse
Solution
9 x + 4 y ∧ 2 + 18 x = 16 9 x + 4 y ^ {\wedge} 2 + 18 x = 16 9 x + 4 y ∧ 2 + 18 x = 16 4 y ∧ 2 = 16 − 27 x 4 y ^ {\wedge} 2 = 16 - 27 x 4 y ∧ 2 = 16 − 27 x y ∧ 2 = 4 − 27 / 4 x y ^ {\wedge} 2 = 4 - 27/4 x y ∧ 2 = 4 − 27/4 x y ∧ 2 = − 27 / 4 ( x − 16 / 27 ) y ^ {\wedge} 2 = -27/4 (x - 16/27) y ∧ 2 = − 27/4 ( x − 16/27 )
It is an equation of parabola. Coordinates of vertex are ( 16 / 27 , 0 ) (16/27, 0) ( 16/27 , 0 ) .
Answer: C: Parabola.
www.AssignmentExpert.com