Answer to Question #57314 in Analytic Geometry for Alandin

Question

: What is the equation of the parabola in the vertex form.

0 = y^2 – x – 4y + 3

A: (x + 12)^2 = (y – 4)
B: (x+1) = (y-2)^2
C: (x-1) = (y+2)^2
D: (x-3) = (y-2)^2





: Graph the parabola. The graph scales 6 tall and 8 wide.

(x+2) = (y-3)^2

(x-2)^2 = 4(y+3)

(x+3)^2 = 4(y+2)

(x-2) = -4(y-3)^2


: What is the equation of the parabola, in vertex form, with vertex at (2, -4) and driectrix y = - 6

A: (y+6)^2 = -8(x+2)
B: (x+2)^2 = 8(y+4)
C: (x-2)^2 = 8(y+4)
D: (y+4)^2 = 8(x-2)


: If the graph of the following parabola is shifted two units left and three units down, what is the resulting equation?

X = - 8y^2

A: (x-3) = -8(y+2)^2

B: (x+2) = -8(y+3)^2

C: (x+3) = -8(y-2)^2

D: (x-2) = -8(y-3)^2