Question #56037

Evaluate
(2i−4k)×(i+2j)

8i−4j+4k

2i+4j+3k

3i+4j+2k

5i−3j−k

Expert's answer

Answer on Question #56037 – Math – Analytic Geometry

Evaluate (2i4k)×(i+2j)(2i - 4k) \times (i + 2j).

a) 8i4j+4k8i - 4j + 4k

b) 2i+4j+3k2i + 4j + 3k

c) 3i+4j+2k3i + 4j + 2k

d) 5i3jk5i - 3j - k

Solution

The cross (vector) product can be rewritten in the following form:


(2i4k)×(i+2j)=ijk204120=i0420j2410+k2012==8i4j+4k.(2i - 4k) \times (i + 2j) = \begin{vmatrix} i & j & k \\ 2 & 0 & -4 \\ 1 & 2 & 0 \end{vmatrix} = i \begin{vmatrix} 0 & -4 \\ 2 & 0 \end{vmatrix} - j \begin{vmatrix} 2 & -4 \\ 1 & 0 \end{vmatrix} + k \begin{vmatrix} 2 & 0 \\ 1 & 2 \end{vmatrix} = \\ = 8i - 4j + 4k.


Answer: (2i4k)×(i+2j)=8i4j+4k.(2i - 4k) \times (i + 2j) = 8i - 4j + 4k.

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