Question #46163

Find the path traced by the centre of the sphere which touches the lines x/y=y/-1z/2
and 2x=y,y-z=0 .

Expert's answer

Answer on Question #46163 – Math – Analytic Geometry

Find the path traced by the center of the sphere which touches the lines xy=y1=z2\frac{x}{y} = \frac{y}{-1} = \frac{z}{2} and 2x=y,yz=02x = y, y - z = 0.

Solution

The path traced by the center of the sphere is the locus. The radius of the sphere equals to the distance between the center of the sphere and the points on following lines.


r=xy=y1=z2;s=x1=y2=z2.r = \frac{x}{y} = \frac{y}{-1} = \frac{z}{2}; \quad s = \frac{x}{1} = \frac{y}{2} = \frac{z}{2}.R2=(xx1)2+(yy1)2+(zz1)2=(xx2)2+(yy2)2+(zz2)2.R^2 = (x - x_1)^2 + (y - y_1)^2 + (z - z_1)^2 = (x - x_2)^2 + (y - y_2)^2 + (z - z_2)^2.(x+r2)2+(y+r)2+(z2r)2=(xs)2+(y2s)2+(z2s)2.(x + r^2)^2 + (y + r)^2 + (z - 2r)^2 = (x - s)^2 + (y - 2s)^2 + (z - 2s)^2.2r2x+2ry4rz+(r4+r2+4r2)=2sx4sy4sz+(s2+4s2+4s2).2r^2x + 2ry - 4rz + (r^4 + r^2 + 4r^2) = -2sx - 4sy - 4sz + (s^2 + 4s^2 + 4s^2).(2r2+2s)x+(2r+4s)y+(4s4r)z+(r4+5r29s2)=0.(2r^2 + 2s)x + (2r + 4s)y + (4s - 4r)z + (r^4 + 5r^2 - 9s^2) = 0.


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