Question #45121

Find the rectangular coordinates of the point with the polar coordinates (8, 3 divided by 2 pi).

Expert's answer

Answer on Question #45121 – Math – Analytic Geometry

Question. Find the rectangular coordinates of the point with the polar coordinates (8,32π)(8,\frac{3}{2}\pi).

Solution. Recall that the relation between rectangular (x,y)(x,y) and polar coordinates (r,ϕ)(r,\phi) is given by the following formulas:


x=rcosϕ,y=rsinϕ.x = r \cos \phi, \qquad y = r \sin \phi.


In our problem


r=8,ϕ=32π.r = 8, \qquad \phi = \frac{3}{2} \pi.


Therefore


x=rcosϕ=8cos(32π)=80=0,x = r \cos \phi = 8 \cdot \cos \left(\frac{3}{2} \pi\right) = 8 \cdot 0 = 0,y=rsinϕ=8sin(32π)=8(1)=8.y = r \sin \phi = 8 \cdot \sin \left(\frac{3}{2} \pi\right) = 8 \cdot (-1) = -8.


Thus the rectangular coordinates of the point with the polar coordinates (8,32π)(8,\frac{3}{2}\pi) are


(0,8).(0, -8).


Answer. (0,8)(0, -8).

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