Question #45072

Check whether the following statements are true or false. Justify your answer with a short explanation or a counter example.
(i) Any line through the origin cuts the sphere x^2+y^2+z^2=4 at exactly two points.
(ii) The plane making intercept at the z-axis and parallel to the xy-plane intersects the cone x^2+y^2 = z^2(tan theta)^2 in a circle.
(iii) There exists no line with 1/under-root3 ,1/under-root2 ,1/under-root6 as direction cosines.
(iv) The tangent planes at the extremities of any axis of an ellipsoid are perpendicular.
(v) A section of an elliptic paraboloid by a plane is always an ellipse.
(vi) The curve xy^2+yx^2=0 is symmetric about the origin.
(vii) There exists a unique line which is perpendicular to the lines x=y=z/2 and x=y= -z.
(viii) The plane 3x+4y+2z=1 touches the conicoid 3x^2+2y^2=z^2=1.
(ix) The xy- plane intersects the sphere x^2+y^2+z^2+2x-z=2 in a great circle.
(x) Non degenerate conics are non-central.
1

Expert's answer

2014-08-22T14:31:22-0400

Answer on Question #45072 – Math - Analytic Geometry

Problem.

Check whether the following statements are true or false. Justify your answer with a short explanation or a counter example.

(i) Any line through the origin cuts the sphere x2+y2+z2=4x^2 + y^2 + z^2 = 4 at exactly two points.

(ii) The plane making intercept at the zz-axis and parallel to the xyxy-plane intersects the cone x2+y2=z2x^2 + y^2 = z^2 (tan theta) in a circle.

(iii) There exists no line with 1/under-root3, 1/under-root2, 1/under-root6 as direction cosines.

(iv) The tangent planes at the extremities of any axis of an ellipsoid are perpendicular.

(v) A section of an elliptic paraboloid by a plane is always an ellipse.

(vi) The curve xy2+yx2=0xy^2 + yx^2 = 0 is symmetric about the origin.

(vii) There exists a unique line which is perpendicular to the lines x=y=z/2x = y = z/2 and x=y=zx = y = -z.

(viii) The plane 3x+4y+2z=13x + 4y + 2z = 1 touches the conicoid 3x2+2y2=z2=13x^2 + 2y^2 = z^2 = 1.

(ix) The xyxy-plane intersects the sphere x2+y2+z2+2xz=2x^2 + y^2 + z^2 + 2x - z = 2 in a great circle.

(x) Non degenerate conics are non-central.

Solution.

(i) The statement is true.

The lines through the origin has equation x=αt,y=βt,z=γtx = \alpha t, y = \beta t, z = \gamma t (where α,β,γR\alpha, \beta, \gamma \in \mathbb{R}). This line intersects sphere at (αt0,βt0,γt0)(\alpha t_0, \beta t_0, \gamma t_0) and (αt0,βt0,γt0)(- \alpha t_0, -\beta t_0, -\gamma t_0) (where (α2+β2+γ2)t02=4(\alpha^2 + \beta^2 + \gamma^2)t_0^2 = 4).

(ii) The statement is false.

The equation of xyxy-plane is z=0z = 0. Hence if (x0,y0,z0)(x_0, y_0, z_0) is the point from the intersection, then z0=0z_0 = 0 and x02+y02=z02tan2θ=0x_0^2 + y_0^2 = z_0^2 \tan^2 \theta = 0 or x0=0x_0 = 0 and y0=0y_0 = 0. Therefore xyxy-plane intersects the cone x2+y2=z2(tanθ)2x^2 + y^2 = z^2 (\tan \theta)^2 in a point.

(iii) The statement is false.

The line x1/3=y1/2=z1/6\frac{x}{1/\sqrt{3}} = \frac{y}{1/\sqrt{2}} = \frac{z}{1/\sqrt{6}} has direction vector (13,12,16)\left(\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{6}}\right), (13)2+(12)2+(16)2=1\left(\frac{1}{\sqrt{3}}\right)^2 + \left(\frac{1}{\sqrt{2}}\right)^2 + \left(\frac{1}{\sqrt{6}}\right)^2 = 1, so

direction the direction cosines are 13,12,16\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{6}}.

(iv) The statement is false.

The tangent planes at the extremities of a xx-axis of an ellipsoid x2+y2+z2=1x^2 + y^2 + z^2 = 1 are x=1x = 1 and x=1x = -1. This plane is parallel.

(v) The statement is false.

z=x2+y2z = x^2 + y^2 is elliptic paraboloid. The intersection of z=x2+y2z = x^2 + y^2 with plane y=0y = 0 is z=x2z = x^2.

(vi) The statement is true.

Let l ⁣:xy2+yx2=0l \colon xy^2 + yx^2 = 0. If (x,y)l(x, y) \in l, then (x,y)l(-x, -y) \in l (as xy2+yx2=0=(xy2+yx2)=(x)(y)2+(y)(x)2xy^2 + yx^2 = 0 = -(xy^2 + yx^2) = (-x)(-y)^2 + (-y)(-x)^2). Therefore the curve is symmetric about the origin.

(vii) The statement is true.

Suppose that the direction vector of line ll perpendicular to the lines x=y=z2x = y = \frac{z}{2} and x=y=zx = y = -z is (a,b,c)(a, b, c). Then 1a+1b+2c=01 \cdot a + 1 \cdot b + 2 \cdot c = 0 and 1a+1bc=01 \cdot a + 1 \cdot b - c = 0. Hence c=0c = 0 and a+b=0a + b = 0.

Therefore the direction vector of line ll is (1,1,0)(1, -1, 0). If (x0,y0,z0)(x_0, y_0, z_0) is point of intersection of lines ll and x=y=zx = y = -z, then (x0,y0,z0)=(x0,x0,x0)(x_0, y_0, z_0) = (x_0, x_0, -x_0). Hence the line ll has equation x=t+x0x = t + x_0, y=t+x0y = -t + x_0, z=x0z = -x_0. There should exist point of intersection of ll and x=y=z2x = y = \frac{z}{2}. Hence there should exist t0t_0 such that t0+x0=t0+x0=x02t_0 + x_0 = -t_0 + x_0 = -\frac{x_0}{2}, so t0=x0=0t_0 = x_0 = 0. Hence the equation of ll is x=tx = t, y=ty = -t, z=0z = 0, so there exist a unique line.

(viii) The statement is false.

The coincoid 3x2+2y2=z2=13x^2 + 2y^2 = z^2 = 1 is union two curves (ellipses).

(ix) The statement is true.

The intersection is curve z=0z = 0, x2+y2+2x=2x^2 + y^2 + 2x = 2 or (x+1)2+y2=(3)2(x + 1)^2 + y^2 = (\sqrt{3})^2 it is circle.

(x) The statement is false.

The conic x2+y2+z2=1x^2 + y^2 + z^2 = 1 is non degenerate and has center (0,0,0)(0,0,0).

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