Question #42440

Let u = <-3, 4>, v = <8, 2>. Find u + v.

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Expert's answer

2014-05-17T08:07:07-0400

Answer on Question #42440 – Math - Analytic Geometry

Let u=(3,4),v=(8,2)\mathbf{u} = (-3,4), \mathbf{v} = (8,2).

Find u+v\mathbf{u} + \mathbf{v}.

Given two vectors u=(u1,u2)\mathbf{u} = (u_{1}, u_{2}) and v=(v1,v2)\mathbf{v} = (v_{1}, v_{2}) in the Euclidean plane, the sum is given by:


u+v=(u1+v1,u2+v2)\overline{\mathbf{u} + \mathbf{v}} = (u_{1} + v_{1}, u_{2} + v_{2})


In other words, vector addition is just like ordinary addition: component by component.

Notice that if you add together two 2-dimensional vectors you must get another 2-dimensional vector as your answer. Addition of 3-dimensional vectors will yield 3-dimensional answers. 2- and 3-dimensional vectors belong to different vector spaces and cannot be added. These same rules apply when we are dealing with scalar multiplication.

Thus,


u+v=(3+8,4+2)\overline{\mathbf{u} + \mathbf{v}} = (-3 + 8, 4 + 2)u+v=(5,6)\overline{\mathbf{u} + \mathbf{v}} = (5,6)


Answer: u+v=(5,6)\overline{\mathbf{u} + \mathbf{v}} = (5,6)

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