Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <-5, -4>, v = <-4, -3>

help me please

Answer 1

Answer on Question #42437 - Math - Analytic Geometry

$$u = \{-5; -4\}$$ $$v = \{-4; -3\}$$ $$|u| = \sqrt{(-5)^2 + (-4)^2} = 6.4$$ $$|v| = \sqrt{(-4)^2 + (-3)^2} = 5$$ $$u * v = (-5) * (-4) + (-4) * (-3) = 32$$ $$u * v = |u| * |v| * \cos(\widehat{u, v})$$ $$\widehat{u, v} = \arccos\left(\frac{u * v}{|u| * |v|}\right) = \arccos\left(\frac{32}{5 * 6.4}\right) \approx 0$$

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