Question #42422

Let u = <4, 3>. Find the unit vector in the direction of u, and write your answer in component form.


help me please

Expert's answer

Answer on Question #42422 – Math – Analytic Geometry

1. Let u=<4,3>u = <4, 3>. Find the unit vector in the direction of uu, and write your answer in component form.

Solution.

The module of the vector u(4;3)\vec{u}(4;3) is u=42+32=5|\vec{u}| = \sqrt{4^2 + 3^2} = 5.

The unit vector in the direction of uu is n=uu\vec{n} = \begin{vmatrix} \vec{u} \\ \vec{u} \end{vmatrix}. The module of this vector equals to 1, and the direction is the same as the direction of the vector u\vec{u}.

Let write the unit vector in component form: n=15(4;3)=(4355)\vec{n} = \frac{1}{5}(4;3) = \begin{pmatrix} 4 & 3 \\ 5 & 5 \end{pmatrix}.

Answer: (4355)\begin{pmatrix} 4 & 3 \\ 5 & 5 \end{pmatrix}.


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