Answer on Question #42416 – Math – Analytic Geometry
Find a · b.
a = 10 i + 9 j , b = 4 i + 3 j \mathrm{a} = 10\mathrm{i} + 9\mathrm{j},\ \mathrm{b} = 4\mathrm{i} + 3\mathrm{j} a = 10 i + 9 j , b = 4 i + 3 j
what do i have to do with the i.
Solution
i ⃗ \vec{i} i and j ⃗ \vec{j} j are the unit vectors of the X X X and Y Y Y axes. They are perpendicular. So,
i ⃗ ⋅ i ⃗ = 1 , j ⃗ ⋅ j ⃗ = 1 , i ⃗ ⋅ j ⃗ = j ⃗ ⋅ i ⃗ = 0. \vec{i} \cdot \vec{i} = 1,\ \vec{j} \cdot \vec{j} = 1,\ \vec{i} \cdot \vec{j} = \vec{j} \cdot \vec{i} = 0. i ⋅ i = 1 , j ⋅ j = 1 , i ⋅ j = j ⋅ i = 0.
The scalar product of the vectors a ⃗ \vec{a} a and b ⃗ \vec{b} b is
a ⃗ ⋅ b ⃗ = ( 10 i ⃗ + 9 j ⃗ ) ⋅ ( 4 i ⃗ + 3 j ⃗ ) = 10 ⋅ 4 ⋅ ( i ⃗ ⋅ i ⃗ ) + 10 ⋅ 3 ⋅ ( i ⃗ ⋅ j ⃗ ) + 9 ⋅ 4 ⋅ ( j ⃗ ⋅ i ⃗ ) + 9 ⋅ 3 ⋅ ( j ⃗ ⋅ j ⃗ ) = = 40 ⋅ 1 + 30 ⋅ 0 + 36 ⋅ 0 + 27 ⋅ 1 = 67. \begin{array}{l}
\vec{a} \cdot \vec{b} = \left(10\vec{i} + 9\vec{j}\right) \cdot \left(4\vec{i} + 3\vec{j}\right) = 10 \cdot 4 \cdot \left(\vec{i} \cdot \vec{i}\right) + 10 \cdot 3 \cdot \left(\vec{i} \cdot \vec{j}\right) + 9 \cdot 4 \cdot \left(\vec{j} \cdot \vec{i}\right) + 9 \cdot 3 \cdot \left(\vec{j} \cdot \vec{j}\right) = \\
= 40 \cdot 1 + 30 \cdot 0 + 36 \cdot 0 + 27 \cdot 1 = 67.
\end{array} a ⋅ b = ( 10 i + 9 j ) ⋅ ( 4 i + 3 j ) = 10 ⋅ 4 ⋅ ( i ⋅ i ) + 10 ⋅ 3 ⋅ ( i ⋅ j ) + 9 ⋅ 4 ⋅ ( j ⋅ i ) + 9 ⋅ 3 ⋅ ( j ⋅ j ) = = 40 ⋅ 1 + 30 ⋅ 0 + 36 ⋅ 0 + 27 ⋅ 1 = 67.
Answer: 67.
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