Question #42416

Find a ⋅ b.

a = 10i + 9j, b = 4i + 3j

what do i have to do with the i
1

Expert's answer

2014-05-15T10:39:04-0400

Answer on Question #42416 – Math – Analytic Geometry

Find a · b.


a=10i+9j, b=4i+3j\mathrm{a} = 10\mathrm{i} + 9\mathrm{j},\ \mathrm{b} = 4\mathrm{i} + 3\mathrm{j}


what do i have to do with the i.

Solution

i\vec{i} and j\vec{j} are the unit vectors of the XX and YY axes. They are perpendicular. So,


ii=1, jj=1, ij=ji=0.\vec{i} \cdot \vec{i} = 1,\ \vec{j} \cdot \vec{j} = 1,\ \vec{i} \cdot \vec{j} = \vec{j} \cdot \vec{i} = 0.


The scalar product of the vectors a\vec{a} and b\vec{b} is


ab=(10i+9j)(4i+3j)=104(ii)+103(ij)+94(ji)+93(jj)==401+300+360+271=67.\begin{array}{l} \vec{a} \cdot \vec{b} = \left(10\vec{i} + 9\vec{j}\right) \cdot \left(4\vec{i} + 3\vec{j}\right) = 10 \cdot 4 \cdot \left(\vec{i} \cdot \vec{i}\right) + 10 \cdot 3 \cdot \left(\vec{i} \cdot \vec{j}\right) + 9 \cdot 4 \cdot \left(\vec{j} \cdot \vec{i}\right) + 9 \cdot 3 \cdot \left(\vec{j} \cdot \vec{j}\right) = \\ = 40 \cdot 1 + 30 \cdot 0 + 36 \cdot 0 + 27 \cdot 1 = 67. \end{array}


Answer: 67.

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