Question #40431

if the line has a slope of 5 and y-intercept of -3,what would be the equation in the form of Ax+By+c=0?
1

Expert's answer

2014-04-10T13:10:35-0400

Answer on Question #40431 – Math – Analytical Geometry

if the line has a slope of 5 and y-intercept of -3, what would be the equation in the form of Ax+By+c=0Ax + By + c = 0?

Solution.

The statement (the straight line has a slope of 5 and y-intercept of -3) means the equation of this straight line is y=kx+b,k=5,b=3y = kx + b, k = 5, b = -3.

Therefore, y=5x3y = 5x - 3. Rewrite the last equation as 5xy3=05x - y - 3 = 0 and thus, we obtain the equation in the form of Ax+By+c=0Ax + By + c = 0, where A=5,B=1,c=3A = 5, B = -1, c = -3.

Answer: 5xy3=05x - y - 3 = 0

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