Question #351011

  • Find the area of ​​a triangle constructed on vectors а‾ = ı‾ + ȷ‾ , ̅b‾=2ȷ‾.

Expert's answer

a⃗×b⃗=∣i⃗j⃗k⃗110020∣=k⃗(2−0)=2k⃗\vec{a}\times\vec{b}=\begin{vmatrix} \vec{i} & \vec{j}& \vec{k} \\ 1 & 1 & 0 \\ 0 & 2 & 0 \\ \end{vmatrix}=\vec{k}(2-0)=2\vec{k}Area=A=12∣a⃗×b⃗∣=12(2)=1(units2)Area=A=\dfrac{1}{2}|\vec{a}\times\vec{b}|=\dfrac{1}{2}(2)=1({units}^2)

1 square unit.


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