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Question #351011
Find
the
area
of
a
triangle constructed on vectors а‾ = ı‾ + ȷ‾ , ̅b‾=2ȷ‾.
Expert's answer
a
⃗
×
b
⃗
=
∣
i
⃗
j
⃗
k
⃗
1
1
0
0
2
0
∣
=
k
⃗
(
2
−
0
)
=
2
k
⃗
\vec{a}\times\vec{b}=\begin{vmatrix} \vec{i} & \vec{j}& \vec{k} \\ 1 & 1 & 0 \\ 0 & 2 & 0 \\ \end{vmatrix}=\vec{k}(2-0)=2\vec{k}
a
×
b
=
∣
∣
i
1
0
j
1
2
k
0
0
∣
∣
=
k
(
2
−
0
)
=
2
k
A
r
e
a
=
A
=
1
2
∣
a
⃗
×
b
⃗
∣
=
1
2
(
2
)
=
1
(
u
n
i
t
s
2
)
Area=A=\dfrac{1}{2}|\vec{a}\times\vec{b}|=\dfrac{1}{2}(2)=1({units}^2)
A
re
a
=
A
=
2
1
∣
a
×
b
∣
=
2
1
(
2
)
=
1
(
u
ni
t
s
2
)
1 square unit.
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#339914
on Dec 2023
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