Question #32967

the equation of the line passing through the points A and B. A(5,1/2), B(-1,3/4)

Expert's answer

The equation of the line passing through the points A and B. A(5,1/2),B(1,3/4)A(5,1/2), B(-1,3/4).

**Solution:**

First find the slope


k=y2y1x2x1k = \frac{y_2 - y_1}{x_2 - x_1}k=341215=3246=146=124k = \frac{\frac{3}{4} - \frac{1}{2}}{-1 - 5} = \frac{\frac{3 - 2}{4}}{-6} = \frac{\frac{1}{4}}{-6} = -\frac{1}{24}


So slope of the line is equal 124-\frac{1}{24}

Then use y=kx+by = kx + b, and substitute one set of points into the equation:


12=1245+b\frac{1}{2} = -\frac{1}{24} * 5 + bb=12+524=1724b = \frac{1}{2} + \frac{5}{24} = \frac{17}{24}


The equation is y=124x+1724y = -\frac{1}{24} x + \frac{17}{24}

**Answer:** y=124x+1724y = -\frac{1}{24} x + \frac{17}{24}

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