Task. Represent the given velocity v=230km/h in the direction α=200 degrees. Solution. The vector v is shown in the following figure:

We should find coordinates (vx,vy) of its end. By definition
vx=vcosα,vy=vsinα.
Substituting values we get
vx=vcosα=230∗cos200∘=230∗(−0.93969)=−216.13km/h,vy=vsinα=230∗sin200∘=230∗(−0.34202)=−78.665km/h.
Thus v=(−216.13,−78.665) .