Answer to Question #294752 in Analytic Geometry for Denver

Question #294752

How to find the coordinate of p and q if the circle cuts the x-axis at the points p and q in 2x^2 +2y^2 -8x +5y -10=0

1
Expert's answer
2022-02-11T11:58:51-0500

Since the circle cuts the x-axis then "y=0".

Substituting "y=0" into the given equation of the circle, "2x^2 +2y^2 -8x +5y -10=0", we have

"2x^2-8x-10=0\\\\\n\\Rightarrow x^2-4x-5=0\\\\\n\\Rightarrow (x-5)(x+1)=0\\Rightarrow x=-1,5"

Thus, without loss of generality, the circle cuts the x-axis at P"(-1,0)" and Q"(5,0)"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS