Find the equations of the line through (1,3, 4 ) and parallel to the line joining the points (−4, 5, 3) and (8, 9, 7)
Solution;
AB→=(8,9,7)−(−4,5,3)\overrightarrow{AB}=(8,9,7)-(-4,5,3)AB=(8,9,7)−(−4,5,3)
AB→=(12,4,4)\overrightarrow{AB}=(12,4,4)AB=(12,4,4)
13(AB→)=(3,1,1)\frac13( \overrightarrow{AB})=(3,1,1)31(AB)=(3,1,1)
Vector form of equation through (1,3,4) is;
(x,y,z)=(1,3,4)+t(3,1,1)
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