Find the equations of the line through (1,3, 4 ) and parallel to the line joining the points (β4, 5, 3) and (8, 9, 7)
Solution;
"\\overrightarrow{AB}=(8,9,7)-(-4,5,3)"
"\\overrightarrow{AB}=(12,4,4)"
"\\frac13(\n \\overrightarrow{AB})=(3,1,1)"
Vector form of equation through (1,3,4) is;
(x,y,z)=(1,3,4)+t(3,1,1)
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