Answer to Question #293422 in Analytic Geometry for Kaka

Question #293422

How to find the coordinate of p and q if the circle cuts the x-axis at the points p and q in 2x^2 +2y^2 -8x +5y -10=0

1
Expert's answer
2022-02-14T13:04:58-0500

Since the circle cuts the x-axis then y=0y=0.

Substituting y=0y=0 into the given equation of the circle, 2x2+2y28x+5y10=02x^2 +2y^2 -8x +5y -10=0, we have

2x28x10=0x24x5=0(x5)(x+1)=0x=1,52x^2-8x-10=0\\ \Rightarrow x^2-4x-5=0\\ \Rightarrow (x-5)(x+1)=0\Rightarrow x=-1,5

Thus, without loss of generality, the circle cuts the x-axis at P(1,0)(-1,0) and Q(5,0)(5,0)

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment