In the triangle ABC having vertices at A(-2,5), B(6,1) and C(-2,-3) , find the length of the median from vertex B to side AC .
Find the coordinates of the point E - the midpoint of AC:
E(−2−22;5−32)⇒E(−2; 1)E\left( {\frac{{ - 2 - 2}}{2};\frac{{5 - 3}}{2}} \right) \Rightarrow E\left( { - 2;\,1} \right)E(2−2−2;25−3)⇒E(−2;1)
Thenthe length of the median is
BE=(−2−6)2+(1−1)2=8BE = \sqrt {{{\left( { - 2 - 6} \right)}^2} + {{\left( {1 - 1} \right)}^2}} = 8BE=(−2−6)2+(1−1)2=8
Answer: 8
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments