Question

A single-lane street 10 ft wide goes through a semicircular tunnel with radius 9 ft. How high is the tunnel at the edge of each lane? Roun off to 2 decimal places.

Answer 1

Solution;

$R=9ft$

$x=\frac{10}{2}=5ft$

But;

$x^2+y^2=r^2$

$y^2=9^2-5^2$

$y=\sqrt{56}=7.48ft$