A single-lane street 10 ft wide goes through a semicircular tunnel with radius 9 ft. How high is the tunnel at the edge of each lane? Roun off to 2 decimal places.
Solution;
R=9ftR=9ftR=9ft
x=102=5ftx=\frac{10}{2}=5ftx=210=5ft
But;
x2+y2=r2x^2+y^2=r^2x2+y2=r2
y2=92−52y^2=9^2-5^2y2=92−52
y=56=7.48fty=\sqrt{56}=7.48fty=56=7.48ft
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