Answer to Question #275786 in Analytic Geometry for Mohammad

Question

With respect to the bar of chocolate, where is their center of mass?

The initial x-coordinates of James and Ramon are -10.0 m and +10.0 m respectively,

so the x-coordinate of the center of mass is:

Formula:

Solution:

Final Answer

Answer 1

Given Jame's mass $m_J=90.0$ kg, Ramon's mass $m_R=60.0$ kg, $x_{0J}=-10.0$ m, $x_{0R}=10.0$ m.

Formula:

$$x_{CM}=\dfrac{x_{0J}m_J+x_{0R}m_R}{m_J+m_R}$$

Solution

$$x_{CM}=\dfrac{-10.0m(90.0kg)+10.0m(60.0kg)}{90.0kg+60.0kg}$$

$$=-2.0m$$

Final answer:

The x-coordinate of the center of mass is $-2.0$ m.