Question #275786

With respect to the bar of chocolate, where is their center of mass?

The initial x-coordinates of James and Ramon are -10.0 m and +10.0 m respectively,

so the x-coordinate of the center of mass is:

Formula:

Solution:

Final Answer


1
Expert's answer
2021-12-06T15:05:20-0500

Given Jame's mass mJ=90.0m_J=90.0 kg, Ramon's mass mR=60.0m_R=60.0 kg, x0J=10.0x_{0J}=-10.0 m, x0R=10.0x_{0R}=10.0 m.

Formula:


xCM=x0JmJ+x0RmRmJ+mRx_{CM}=\dfrac{x_{0J}m_J+x_{0R}m_R}{m_J+m_R}

Solution


xCM=10.0m(90.0kg)+10.0m(60.0kg)90.0kg+60.0kgx_{CM}=\dfrac{-10.0m(90.0kg)+10.0m(60.0kg)}{90.0kg+60.0kg}

=2.0m=-2.0m

Final answer:

The x-coordinate of the center of mass is 2.0-2.0 m.


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