Find the equation of a line that passes through the point (2,1) and has a gradient of
−
1
3
.
Leave your answer in the form
y
=
m
x
+
c
for the line
y=mx+cy=mx+cy=mx+c
m is gradient
we have: m=1/3m=1/3m=1/3
so, for point (2,1):
1=2/3+c1=2/3+c1=2/3+c
c=1−2/3=1/3c=1-2/3=1/3c=1−2/3=1/3
equation of a line:
y=x/3+1/3y=x/3+1/3y=x/3+1/3
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