Answer to Question #259872 in Analytic Geometry for Hamad

Question #259872

Two forces act a point The magnitude of the Two forces are F, 2 newton and the measure of the angle between them is 60, if their resultant equal 2√3 newton,then F =newton


1
Expert's answer
2021-11-02T14:12:19-0400

Given: Two forces as 2 N and F N, angle between them is 60°60\degreeand their resultant is 232\sqrt{3} N.

We know that,

R=R12+R22+2R1R2cosθR=\sqrt{R_1^2+R_2^2+2R_1R_2\cos\theta}

23=22+F2+2×2×Fcos60°23=4+F2+2F [cos60°=12]12=4+F2+2FF2+2F8=0(F2)(F+4)=0F=2,4As the magnitude of force can’t be negative So,F=2N\Rightarrow 2\sqrt{3}=\sqrt{2^2+F^2+2\times2\times F\cos 60\degree} \\\Rightarrow 2\sqrt{3}=\sqrt{4+F^2+2F} \ [\because \cos 60\degree=\frac 1 2] \\\Rightarrow 12=4+F^2+2F \\\Rightarrow F^2+2F-8=0 \\\Rightarrow (F-2)(F+4)=0 \\\Rightarrow F=2,-4 \\\text{As the magnitude of force can't be negative } \\So, F=2N


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