Question #255675

Find the magnitude of the vector v=2i−5j+4k


1
Expert's answer
2021-10-25T15:25:50-0400

Mv2=22+(5)2+424+25+1645M_v ^2=2^2+(-5)^2+4^2\\4+25+16\\45

Magnitude=45=\sqrt{45}



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