Answer to Question #255663 in Analytic Geometry for Samzola

Question

Find the magnitude of the vector v=2i−5j+4k

Answer 1

Magnitude of any vector is $|xi+yj+zk|=\sqrt{x^2+y^2+z^2}$

Hence the magnitude of this vector$=\sqrt{2^2+(-5)^2+4^2}$

$=\sqrt{45}$