Find the parametric equation of x=a(1+cos theta)
Here x=a(1+cosθ)x=a(1+cos \theta)x=a(1+cosθ) is already in parametric form as x=f(θ)x =f(\theta)x=f(θ)
We can add y=a(1−sinθ)y=a(1-sin \theta)y=a(1−sinθ) to make y=f(θ)y=f(\theta)y=f(θ)
Now, both xxx and yyy are functions of θ\thetaθ .
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