Let L be the line given by the vector equation (x,y)=(1,1) + t( sqrt(3),1), tR. What is the equation of the image of L after being rotated 15 deg about (1,1) and then translated by vector u=(-1,1)
The equation of a line in vector form is
where a is the position vector of a point on the line and b is a vector parallel to the line.
Rotating the line through and angle is equivalent to rotating b through the same angle.
In this case:
The slope of the line segment from the origin to the head of this vector is
and hence its inclination to the positive X axis is
If we rotate this vector by its inclination to the positive X axis becomes
Hence the slope of b1 after rotating:
b1 can then be represented by the position vector of point
Translating the line through u=(-1,1) is equivalent to translating the given point on the line by
Hence, after this translation the point (1,1) becomes (0,2)
Thus, it can be seen that after the given rotation and translation the vector equation of the line becomes
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