Question #242349

A parabolic reflector has a diameter of 20cm and it's depth is 5cm. Find the focus show solution and graph


1
Expert's answer
2021-09-27T16:10:56-0400


Equation of parabola 

y2=2pxy^2=2px

x=10=>y=2p10=20p=5=>20p=25=>p=25\20=1.25x=10 => y=\sqrt{2p\cdot 10}=\sqrt{20p}=5=>20p=25=>p=25\20=1.25\\

Therefore focus F(0,p/2) is F(0,0.625 cm)

Focus lies on the axis of symmetry at a distance 0.625 cm from vertex of parabolic reflector



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS