Question

Given the equation of a circle as X^2+Y^2+4x-6y=-

Answer 1

$$x^2+y^2+4x-6y=-4$$

$$x^2+4x+4+y^2-6y+9=9$$

$$(x+2)^2+(y-3)^2=9$$

The equation of the circle with center $(-2, 3)$ and radius $r=3.$