point m is the midpoint of xy. xm=5x+3 and my =9x -25 find x xm my xy
Solution;
Given;
xm=5x+3x_m=5x+3xm=5x+3
ym=9x−25y_m=9x-25ym=9x−25
If m is the midpoint of xy,then;
xm=ymx_m=y_mxm=ym
Hence;
5x+3=9x−255x+3=9x-255x+3=9x−25
4x=284x=284x=28
x=7x=7x=7
By substitution;
xm=5x+3=5(7)+3=38x_m=5x+3=5(7)+3=38xm=5x+3=5(7)+3=38
ym=9x−25=9(7)−25=38y_m=9x-25=9(7)-25=38ym=9x−25=9(7)−25=38
But;
xy=xm+ymxy=x_m+y_mxy=xm+ym
xy=38+38=76xy=38+38=76xy=38+38=76
Answer;
xm=38x_m=38xm=38
ym=38y_m=38ym=38
xy=76xy=76xy=76
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