Question #22902

Find the sum of the measures of the interiors angles of a hexagon

Expert's answer

Task:

Find the sum of interior angles of a hexagon

Solution:


For any convex polygon the sum of the interior angles:


α=(n2)180=4180=720\sum \alpha = (n - 2) \cdot 180{}^{\circ} = 4 \cdot 180{}^{\circ} = 720{}^{\circ}n(number of sides)n - (\text{number of sides})n=6n = 6α=(62)180=720\sum \alpha = (6 - 2) \cdot 180{}^{\circ} = 720{}^{\circ}

Answer:

α=720\sum \alpha = 720{}^{\circ}

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