The volume V of the parallelopiped that has u, v, w as adjacent edges is
given by: V = |u.(v × w)|. If u.(v × w) = 0, then u, v, w lie in the same
plane. Thus, find the volume of the parallelopiped formed by the followings:
u =< 1, 2, −1 >, v =< 2, −1, 2 >, w =< 2, −3, 4 >.
"v\\times{w}=\\begin{vmatrix}\n i & j & k \\\\\n 2 & -1 & 2\\\\\n 2 & -3 & 4\n\\end{vmatrix}=i(4(-1)-2(-3))-j(4(2)-2(2))+k(2(-3)-2(-1))=2i-4j-4k\\\\\nu\\cdot(v\\times{w})=(i+2j-k)(2i-4j-4k)=2-8+4=-2\\\\\nV=|u\\cdot(v\\times{w})|=|-2|=2"
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