If p is a parameter of positive numbers, show that all members of the family of ellipses x2/ (a2 + p) + y2 / (b2 + p) = 1 have the same foci.
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Expert's answer
2021-08-18T12:39:20-0400
If the equation of an ellipse is m2x2+n2y2=1, the the foci are (−c,0) and (c,0), where c=m2−n2. In our case,
c=m2−n2=(a2+p)2−(b2+p)2=a2+p−(b2+p)=a2−b2.
We conclude that the foci are (−a2−b2,0) and (a2−b2,0). Since the foci do not depend on the parameter p, the family of ellipses a2+px2+b2+py2=1 have the same foci.
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