The tangents at the points P(ap2 , 2ap) and Q(aq2 , 2aq) on the parabola y2= 4ax intersect at the point R. Given that the tangent at P is perpendicular to the chord OQ, where O is the origin, find the equation of the locus of R as p varies.
Answer:-
"P(ap^2,2ap), Q(aq^2,2aq)\\\\\ny^2=4ax"
The tangents is
"y\\cdot y_0=2a(x+x_0)"
PR:
"y\\cdot 2ap=2a(x+ap^2)\\\\\nx-py+ap^2=0"
QR:
"y\\cdot 2aq=2a(x+aq^2)\\\\\nx-qy+aq^2=0"
R=PR"\\cap" QR
"x-py+ap^2=0\\\\\nx-qy+aq^2=0\\\\\ny=\\frac{a(p^2-q^2)}{q-p}=a(p+q)\\\\\nx=aqp\\\\\nR(aqp,a(p+q))"
OQ:
"\\frac{x-0}{aq^2-0}=\\frac{y-0}{2aq-0}\\\\\ny=\\frac{2}{q}x\\\\\nk_{OQ}=\\frac{2}{q}"
OQ"\\bot" RP
"k_{RP}=-\\frac{1}{k_{OQ}}=-\\frac{q}{2}"
RP:
"y=\\frac{1}{p}x+ap\\\\\nk_{RP}=\\frac{1}{p}\\\\\n\\frac{1}{p}=-\\frac{q}{2}\\\\\npq=-2"
multiply by a
"apq=-2a\\\\\nx=-2a\\\\\nx+2a=0"
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