Question #207266

With given vectors u=<3,-1,-2> v=<-1,0,2> w=<-6,1,4> compute the expressions below
2.1 v+3w
2.2 u-2v
2.3 - (v+3u)

Expert's answer

2.1


v+3w=⟨−1,0,2⟩+3⟨−6,1,4⟩v+3w=\langle-1,0,2\rangle+3\langle-6,1,4\rangle

=⟨−1+3(−6),0+3(1),2+3(4)⟩=\langle-1+3(-6), 0+3(1), 2+3(4)\rangle




=⟨−19,3,14⟩=\langle-19,3, 14\rangle

2.2


u−2v=⟨3,−1,−2⟩+(−2)⟨−1,0,2⟩u-2v=\langle3,-1,-2\rangle+(-2)\langle-1,0,2\rangle

=⟨3+(−2)(−1),−1+(−2)(0),−2+(−2)(2)⟩=\langle3+(-2)(-1), -1+(-2)(0), -2+(-2)(2)\rangle

=⟨5,−1,−6⟩=\langle5,-1, -6\rangle



2.3


−(v+3u)=−(⟨−1,0,2⟩+3⟨3,−1,−2⟩)-(v+3u)=-(\langle -1,0,2\rangle+3\langle 3,-1,-2\rangle)

=−(⟨−1+3(3),0+3(−1),2+3(−2)⟩)=-(\langle-1+3(3), 0+3(-1), 2+3(-2)\rangle)

=⟨−8,3,4⟩=\langle-8,3, 4\rangle




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