Find equation of the st. line passing through point of intersection of two St.lines L1 : 3x+5y+2=0 , L2 :x-y-4=0 and cuts from postivie part of x-axis 2 length unit
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Expert's answer
2012-12-12T08:51:47-0500
Point of intersection is: 3x+5y+2=0 x-y=4 3(4+y)+5y+2=0 12+9y+2=0 y=14/9 x=14+36/9=50/9 So, for 1 point we have (50/9,14/9) For second, from the task we have (2,0) So, from equation of the line by 2 points we have: 14x/9-(50-2)y/9-10/9=0 14x-48y=28 7x-24y=14
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