The slope of the line which passes through the point (8,14) and (0,4) is
Equation of line is y=kx+cy=kx+cy=kx+c
We know two points on this line, so we can make the system of equations:
{14=8k+c4=c=>k=108=54\begin{cases} 14=8k+c \\ 4=c \end{cases} => k=\frac{10}8=\frac{5}4{14=8k+c4=c=>k=810=45
Next, arctan(k)=arctan(1.25)\arctan(k) =\arctan(1.25)arctan(k)=arctan(1.25).The slope is k=54.k=\frac{5}{4}.k=45.
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