The slope of the line which passes through the point (8,14) and (0,4) is
Equation of line is "y=kx+c"
We know two points on this line, so we can make the system of equations:
"\\begin{cases}\n14=8k+c \\\\\n4=c\n\\end{cases} =>\nk=\\frac{10}8=\\frac{5}4"
Next, "\\arctan(k) =\\arctan(1.25)".The slope is "k=\\frac{5}{4}."
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