Question #182179

Let e = (1, 0) and f = (1, 1) be two points in 

R2 . Find ix - yl, 12x - y I , where x = e + f, 

y = 2e + 2f


1
Expert's answer
2021-04-29T14:38:51-0400

x=e+f=(1,0)+(1,1)=(2,1)y=2e+2f=2x=(4,2)xy=x2x=x=22+12=52xy=2x2x=0=0x = e + f = (1, 0)+(1, 1)= (2, 1) \\ y = 2e + 2f = 2x = (4, 2) \\ |x-y| = |x-2x| = |x| = \sqrt{2^2+1^2} = \sqrt{5} \\ |2x-y| = |2x-2x| = |0| = 0



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