Question #178942

A parallelepiped is defined by the following vectors |š‘Ž| = (2, 3, āˆ’1), |š‘| = (āˆ’1, 0, 2),

and |š‘| = (3, āˆ’1, 2). Find the volume of the parallelepiped. 


Expert's answer

The volume is given by the formula ∣aā‹…āˆ£bƗc∣∣.|a\cdot |b\times c||. We can write b=āˆ’i^+2k^b= -\hat{i}+2\hat{k} and c=3i^āˆ’j^+2k^.c=3\hat{i}-\hat{j}+2\hat{k}. bƗc=i^(āˆ’2Ć—āˆ’1)+j^(2Ɨ3āˆ’(āˆ’1)Ɨ2)+k^(āˆ’1Ć—āˆ’1)b\times c=\hat{i}(-2\times -1)+\hat{j}(2\times 3-(-1)\times 2)+\hat{k}(-1\times -1) =2i^+8j^+k^.=2\hat{i}+8\hat{j}+\hat{k}. Hence aā‹…(bƗc)=a\cdot(b\times c)= (2i^+3j^āˆ’k^)ā‹…(2i^+8j^+k^)(2\hat{i}+3\hat{j}-\hat{k})\cdot (2\hat{i}+8\hat{j}+\hat{k}) = 2Ɨ(2)+(3)Ɨ8āˆ’(1Ɨ1)=27.2\times(2)+(3)\times 8-(1\times 1)=27. Hence volume =∣27∣=27|27|=27 in cube units.


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