The trisect of (x1,y1) and (x2,y2) is (x′,y′) and (x′′,y′′) such that
x′=3x1+2x2, y′=3y1+2y2, x′′=32x1+x2, y′′=32y1+y2.
In our case, x1=−3, y1=5, x2=9, y2=2
x′=3−3+2⋅9=5, y′=35+2⋅2=3, x′′=32(−3)+9=1, y′′=32⋅5+2=4.
The points which trisect the segment joining the points (−3,5) and (9,2) are (5,3) and (1,4).
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