"3x^2 + 3y^2 + 12x + 18y - 43 = 0"
"3(x^2+4x+4)-12+3(y^2+6y+9)-27-43=0"
"3(x+2)^2+3(y+3)^2=82"
"(x+2)^2+(y+3)^2=\\frac{82}{3}"
Answer: centre of circle is "(-2,-3)" and radius is "\\sqrt{\\frac{82}{3}}" .
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