Answer to Question #155561 in Analytic Geometry for ssss

Question #155561

What is the magnitude of the resultant of the forces F1=-3i+2j-k, F2=2i-j+3k and F3=3i+j-k measured in dynes ?


1
Expert's answer
2021-01-14T19:55:56-0500

F1=3i+2jk\vec{F_1}=-3i+2j-k

F2=2ij+3k\vec{F_2}=2i-j+3k

F1=3i+jk\vec{F_1}=3i+j-k

the resultant force is the vector sum of all forces\text{the resultant force is the vector sum of all forces}

F=F1+F2+F3\vec{F}=\vec{F_1}+\vec{F_2}+\vec{F_3}

F=3i+2jk+2ij+3k+3i+jk\vec{F}= -3i+2j-k+2i-j+3k+3i+j-k

F=2i+2j+k\vec{F}=2i+2j+k

F=22+22+1=3|\vec{F}|=\sqrt{2^2+2^2+1}=3

the default force is measured in newtons\text{the default force is measured in newtons}

1J=105dyn1J=10^5dyn

Answer:F=2i+2j+k ;F=3105dyn\vec{F}=2i+2j+k \ ;|\vec{F}|=3*10^5dyn



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