If lattice (C,<=) is a complemented chain, then
a) |C|<=1
b) |C|<=2
c) |C|>1
d) doesn't exist.
1
Expert's answer
2012-09-28T08:37:09-0400
Every chain is bounded: 0 and 1 belongs to C, or they coicide, so |C|=1. If there is third element a, then its complement is such b, that inf(a,b)=0 and sup(a,b)=1. But as it is chain, then we have a<=b or b<=a. If a<=b then 0=inf(a,b)=a and 1=sup(a,b)=b. Case b<=a is similar.
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