Answer to Question #150665 in Analytic Geometry for Haley

Question #150665
find the equation of a parabola with a focus at (0,-1) and a directrix at y=4
1
Expert's answer
2020-12-15T01:24:25-0500

(x0)2+(y+1)2=y4square both sides(x0)2+(y+1)2=(y4)2x2+y2+2y+1=y28y+16x2+y2y2+2y+8y+116=0x2+10y15=0\sqrt{(x-0)^2+(y+1)^2}=y-4\\ \text{square both sides}\\ (x-0)^2+(y+1)^2=(y-4)^2\\ x^2+y^2+2y+1=y^2-8y+16\\ x^2+y^2-y^2+2y+8y+1-16=0\\ x^2+10y-15=0


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