We have the equation of an ellipse with semiaxes a= 32 and b =10\text{We have the equation of an ellipse with semiaxes a= 32 and b =10}We have the equation of an ellipse with semiaxes a= 32 and b =10
x2a2+y2b2=1;a2=b2+c2\frac{x^2}{a^2}+\frac{y^2}{b^2}=1; a^2=b^2+c^2a2x2+b2y2=1;a2=b2+c2
where c half the focal length. \text {where }c \text{ half the focal length. }where c half the focal length.
for x=c value y is the desired value\text{for }x =c \text{ value }y \text{ is the desired value}for x=c value y is the desired value
y2=b2(1−x2a2)y^2= b^2(1-\frac{x^2}{a^2})y2=b2(1−a2x2)
for x=c; y2=b2(1−a2−b2a2)=b4a2\text {for } x=c;\ y^2=b^2(1-\frac{a^2-b^2}{a^2})=\frac{b^4}{a^2}for x=c; y2=b2(1−a2a2−b2)=a2b4
y=b2a=3.125y=\frac{b^2}{a}=3.125y=ab2=3.125
Answer: 3.125 m
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